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#REDIRECT ]
In ], the '''eigenvectors''' (from the ] ''eigen'' meaning "inherent, characteristic") of a ] are non-zero ] which, when operated on by the operator, result in a ] multiple of themselves. The scalar is then called the ] associated with the eigenvector.


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In ] and ] the eigenvectors of a ] or a ] often have important physical significance. In ] the eigenvectors of the governing equations typically correspond to natural modes of vibration in a body, and the eigenvalues to their frequencies. In ], operators correspond to observable variables, eigenvectors are also called '''eigenstates''', and the eigenvalues of an operator represent those values of the corresponding variable that have non-zero probability of occurring.
{{R to plural}}

{{R from subtopic}}
== Examples ==
{{R with history}}
Intuitively, for ]s of two-dimensional space '''R'''<sup>2</sup>, eigenvectors are thus:
{{R unprintworthy}}
* rotation: no real valued eigenvectors. (Complex eigenvalue, eigenvector pairs exist).
}}
* reflection: eigenvectors are perpendicular and parallel to the line of symmetry, the eigenvalues are -1 and 1, respectively
* uniform scaling: all vectors are eigenvectors, and the eigenvalue is the scale factor
* projection onto a line: eigenvectors with eigenvalue 1 are parallel to the line, eigenvectors with eigenvalue 0 are parallel to the direction of projection

== Definition ==
Formally, we define eigenvectors and eigenvalues as follows:
If '''A''' : ''V'' <tt>-></tt> ''V'' is a linear operator on some ] ''V'', '''v''' is a non-zero ] in ''V'' and ''c'' is a scalar (possibly zero) such that

: <math>\mathbf{A} \mathbf{v} = c \mathbf{v},</math>

then we say that '''v''' is an eigenvector of the operator '''A''', and its associated eigenvalue is <math>c</math>. Note that if '''v''' is an eigenvector with ] <math>c</math>, then any non-zero multiple of '''v''' is also an eigenvector with eigenvalue <math>c</math>. In fact, all the eigenvectors with associated eigenvalue <math>c</math>, together with '''0''', form a subspace of ''V'', the ''']''' for the eigenvalue <math>c</math>.

== Identifying eigenvectors ==

For example, consider the ]

: <math>A =
\begin{bmatrix}
\; 0 & 1 & -1 \\
\; 1 & 1 & \; 0 \\
-1 & 0 & \; 1
\end{bmatrix}
</math>

which represents a linear operator '''R'''<sup>3</sup> <tt>-></tt> '''R'''<sup>3</sup>. One can check that

: <math>A \begin{bmatrix} \; 1 \\ \; 1 \\ -1 \end{bmatrix}
= \begin{bmatrix} \; 2 \\ \; 2 \\ -2 \end{bmatrix}
= 2 \begin{bmatrix} \; 1 \\ \; 1 \\ -1 \end{bmatrix}
</math>

and therefore 2 is an eigenvalue of '''A''' and we have found a corresponding eigenvector.

== The characteristic polynomial ==

An important tool for describing eigenvalues of square matrices is the ]: saying that ''c'' is an eigenvalue of '''A''' is equivalent to stating that the system of linear equations ('''A''' - ''c''<b>I</b>) '''x''' = '''0''' (where '''I''' is the identity matrix) has a non-zero solution '''x''' (namely an eigenvector), and so it is equivalent to the ] det('''A''' - ''c'' '''I''') being zero. The function ''p''(''c'') = det('''A''' - ''c''<b>I</b>) is a ] in ''c'' since determinants are defined as sums of products.
This is the ''characteristic polynomial'' of '''A'''; its zeros are precisely the eigenvalues of '''A'''.
If '''A''' is an ''n''-by-''n'' matrix, then its characteristic polynomial has degree ''n'' and '''A''' can therefore have at most ''n'' eigenvalues.

Returning to the example above, if we wanted to compute all of <b>A</b>'s eigenvalues, we could determine the characteristic polynomial first:

:<math>p(x) = \det( A - xI) =
\begin{vmatrix}
-x & 1 & -1\;\; \\
\;\;1 & 1\!-\!x & 0 \\
-1 & 0 & 1\!-\!x
\end{vmatrix}
</math>

::<math> = -x^3 + 2x^2 + x - 2\ </math>
and because <math>p(x) = -(x - 2) (x - 1) (x + 1)</math> we see that the eigenvalues of '''A''' are 2, 1 and -1. The ] states that every square matrix satisfies its own characteristic polynomial.

(In practice, eigenvalues of large matrices are not computed using the characteristic polynomial. Faster and more numerically stable methods are available, for instance the ].)

== Complex eigenvectors ==

Note that if '''A''' is a ] matrix, the characteristic polynomial will have real coefficients, but not
all its roots will necessarily be real. The ] eigenvalues will all be associated to complex eigenvectors.

In general, if '''v'''<sub>1</sub>, ..., '''v'''<sub>''m''</sub> are eigenvectors to ''different'' eigenvalues &lambda;<sub>1</sub>, ..., &lambda;<sub>''m''</sub>, then the vectors '''v'''<sub>1</sub>, ..., '''v'''<sub>''m''</sub> are necessarily ].

The ] for symmetric matrices states that, if '''A''' is a real symmetric ''n''-by-''n'' matrix, then all its eigenvalues are real, and there exist ''n'' linearly independent eigenvectors for '''A''' which all have length 1 and are mutually ].

Our example matrix from above is symmetric, and three mutually orthogonal eigenvectors of '''A''' are

:<math>v_1 = \begin{bmatrix}\; 1 \\ \;1 \\ -1 \end{bmatrix},\quad v_2 = \begin{bmatrix}\; 0\;\\ 1 \\ 1 \end{bmatrix},\quad v_3 = \begin{bmatrix}\; 2 \\ -1 \\ \; 1 \end{bmatrix}.</math>

These three vectors form a ] of '''R'''<sup>3</sup>. With respect to this basis, the linear map represented by '''A''' takes a particularly simple form: every vector '''x''' in '''R'''<sup>3</sup> can be written uniquely as
: <math>\mathbf{x} = x_1 \mathbf{v}_1 + x_2 \mathbf{v}_2 + x_3 \mathbf{v}_3</math>
and then we have
:<math> \mathbf{A x} = 2x_1 \mathbf{v}_1 + x_2 \mathbf{v}_2 - x_3 \mathbf{v}_3.</math>

== Infinite-dimensional spaces ==

The concept of eigenvectors can be extended to ]s
acting on infinite-dimensional ]s or
]s.

There are operators on Banach spaces which have no eigenvectors at
all. For example, take the ] on the Hilbert space
<math>\ell^2(\mathbb{Z})</math>; it is easy to see that any potential
eigenvector can't be square-summable, so none exist. However, any
bounded linear operator on a Banach space <var>V</var> does have
non-empty '''spectrum'''. The spectrum <math>\sigma(T)</math> of the operator<br>
<var>T</var> : <var>V</var> &rarr; <var>V</var> is defined as

:<math>
\sigma(T) = \{ \lambda\in\mathbb{C} : (\lambda 1 - T)\;</math> is not invertible<math>\}. \; </math>
<!-- Does that "is not invertible" really belong in there? -->

Then <math>\sigma(T)</math> is a ] set of complex numbers,
and it is non-empty. When <math>T</math> is a
] (and in particular when <math>T</math> is an
operator between finite-dimensional spaces as above), the
spectrum of <math>T</math> is the same as the set of its eigenvalues.

The spectrum of an operator is an important property in ].

==See also==
*]
*]
*]

==External links==
*
*

{{Linear_algebra}}
] ] ]
]
]
]
]
]

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