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Let be a binary code of length , i.e. a subset of . Let be the minimum distance of , i.e.
where is the Hamming distance between and . The expression represents the maximum number of possible codewords in a binary code of length and minimum distance . The Plotkin bound places a limit on this expression.
Let be the Hamming distance of and , and be the number of elements in (thus, is equal to ). The bound is proved by bounding the quantity in two different ways.
On the one hand, there are choices for and for each such choice, there are choices for . Since by definition for all and , it follows that
On the other hand, let be an matrix whose rows are the elements of . Let be the number of zeros contained in the 'th column of . This means that the 'th column contains ones. Each choice of a zero and a one in the same column contributes exactly (because ) to the sum and therefore
If is even, then the quantity on the right is maximized when and then,
Combining the upper and lower bounds for that we have just derived,
which given that is equivalent to
Since is even, it follows that
On the other hand, if is odd, then is maximized when which implies that
Combining the upper and lower bounds for , this means that
or, using that ,
Since M is an integer,
This completes the proof of the bound.
References
Binary codes with specified minimum distance, M. Plotkin, IRE Transactions on Information Theory, 6:445-450, 1960.