Main article: 1796 United States presidential election
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The 1796 United States presidential election in Rhode Island took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
During this election, Rhode Island cast its 4 electoral votes for John Adams.
Results
1796 United States presidential election in Rhode Island | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Independent | George Washington (incumbent) | — | — | 4 | |
Federalist | John Adams | — | — | 4 | |
Totals | — | — | 8 |
See also
References
- "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
- "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
- Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson, North Carolina: McFarland. p. xii. ISBN 0-7864-1017-5.
State results of the 1796 U.S. presidential election | ||
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Candidates | ||
General articles | ||
Local results | ||
Other 1796 elections |