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Abstract m-space

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(Redirected from AM-space) Concept in order theory

In mathematics, specifically in order theory and functional analysis, an abstract m-space or an AM-space is a Banach lattice ( X , ) {\displaystyle (X,\|\cdot \|)} whose norm satisfies sup { x , y } = sup { x , y } {\displaystyle \left\|\sup\{x,y\}\right\|=\sup \left\{\|x\|,\|y\|\right\}} for all x and y in the positive cone of X.

We say that an AM-space X is an AM-space with unit if in addition there exists some u ≥ 0 in X such that the interval  := { zX : −uz and zu } is equal to the unit ball of X; such an element u is unique and an order unit of X.

Examples

The strong dual of an AL-space is an AM-space with unit.

If X is an Archimedean ordered vector lattice, u is an order unit of X, and pu is the Minkowski functional of [ u , u ] := { x X : u x  and  x x } , {\displaystyle :=\{x\in X:-u\leq x{\text{ and }}x\leq x\},} then the complete of the semi-normed space (X, pu) is an AM-space with unit u.

Properties

Every AM-space is isomorphic (as a Banach lattice) with some closed vector sublattice of some suitable C R ( X ) {\displaystyle C_{\mathbb {R} }\left(X\right)} . The strong dual of an AM-space with unit is an AL-space.

If X ≠ { 0 } is an AM-space with unit then the set K of all extreme points of the positive face of the dual unit ball is a non-empty and weakly compact (i.e. σ ( X , X ) {\displaystyle \sigma \left(X^{\prime },X\right)} -compact) subset of X {\displaystyle X^{\prime }} and furthermore, the evaluation map I : X C R ( K ) {\displaystyle I:X\to C_{\mathbb {R} }\left(K\right)} defined by I ( x ) := I x {\displaystyle I(x):=I_{x}} (where I x : K R {\displaystyle I_{x}:K\to \mathbb {R} } is defined by I x ( t ) = x , t {\displaystyle I_{x}(t)=\langle x,t\rangle } ) is an isomorphism.

See also

References

  1. ^ Schaefer & Wolff 1999, pp. 242–250.

Bibliography

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