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Mellin inversion theorem

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In mathematics, the Mellin inversion formula (named after Hjalmar Mellin) tells us conditions under which the inverse Mellin transform, or equivalently the inverse two-sided Laplace transform, are defined and recover the transformed function.

Method

If φ ( s ) {\displaystyle \varphi (s)} is analytic in the strip a < ( s ) < b {\displaystyle a<\Re (s)<b} , and if it tends to zero uniformly as ( s ) ± {\displaystyle \Im (s)\to \pm \infty } for any real value c between a and b, with its integral along such a line converging absolutely, then if

f ( x ) = { M 1 φ } = 1 2 π i c i c + i x s φ ( s ) d s {\displaystyle f(x)=\{{\mathcal {M}}^{-1}\varphi \}={\frac {1}{2\pi i}}\int _{c-i\infty }^{c+i\infty }x^{-s}\varphi (s)\,ds}

we have that

φ ( s ) = { M f } = 0 x s 1 f ( x ) d x . {\displaystyle \varphi (s)=\{{\mathcal {M}}f\}=\int _{0}^{\infty }x^{s-1}f(x)\,dx.}

Conversely, suppose f ( x ) {\displaystyle f(x)} is piecewise continuous on the positive real numbers, taking a value halfway between the limit values at any jump discontinuities, and suppose the integral

φ ( s ) = 0 x s 1 f ( x ) d x {\displaystyle \varphi (s)=\int _{0}^{\infty }x^{s-1}f(x)\,dx}

is absolutely convergent when a < ( s ) < b {\displaystyle a<\Re (s)<b} . Then f {\displaystyle f} is recoverable via the inverse Mellin transform from its Mellin transform φ {\displaystyle \varphi } . These results can be obtained by relating the Mellin transform to the Fourier transform by a change of variables and then applying an appropriate version of the Fourier inversion theorem.

Boundedness condition

The boundedness condition on φ ( s ) {\displaystyle \varphi (s)} can be strengthened if f ( x ) {\displaystyle f(x)} is continuous. If φ ( s ) {\displaystyle \varphi (s)} is analytic in the strip a < ( s ) < b {\displaystyle a<\Re (s)<b} , and if | φ ( s ) | < K | s | 2 {\displaystyle |\varphi (s)|<K|s|^{-2}} , where K is a positive constant, then f ( x ) {\displaystyle f(x)} as defined by the inversion integral exists and is continuous; moreover the Mellin transform of f {\displaystyle f} is φ {\displaystyle \varphi } for at least a < ( s ) < b {\displaystyle a<\Re (s)<b} .

On the other hand, if we are willing to accept an original f {\displaystyle f} which is a generalized function, we may relax the boundedness condition on φ {\displaystyle \varphi } to simply make it of polynomial growth in any closed strip contained in the open strip a < ( s ) < b {\displaystyle a<\Re (s)<b} .

We may also define a Banach space version of this theorem. If we call by L ν , p ( R + ) {\displaystyle L_{\nu ,p}(R^{+})} the weighted L space of complex valued functions f {\displaystyle f} on the positive reals such that

f = ( 0 | x ν f ( x ) | p d x x ) 1 / p < {\displaystyle \|f\|=\left(\int _{0}^{\infty }|x^{\nu }f(x)|^{p}\,{\frac {dx}{x}}\right)^{1/p}<\infty }

where ν and p are fixed real numbers with p > 1 {\displaystyle p>1} , then if f ( x ) {\displaystyle f(x)} is in L ν , p ( R + ) {\displaystyle L_{\nu ,p}(R^{+})} with 1 < p 2 {\displaystyle 1<p\leq 2} , then φ ( s ) {\displaystyle \varphi (s)} belongs to L ν , q ( R + ) {\displaystyle L_{\nu ,q}(R^{+})} with q = p / ( p 1 ) {\displaystyle q=p/(p-1)} and

f ( x ) = 1 2 π i ν i ν + i x s φ ( s ) d s . {\displaystyle f(x)={\frac {1}{2\pi i}}\int _{\nu -i\infty }^{\nu +i\infty }x^{-s}\varphi (s)\,ds.}

Here functions, identical everywhere except on a set of measure zero, are identified.

Since the two-sided Laplace transform can be defined as

{ B f } ( s ) = { M f ( ln x ) } ( s ) {\displaystyle \left\{{\mathcal {B}}f\right\}(s)=\left\{{\mathcal {M}}f(-\ln x)\right\}(s)}

these theorems can be immediately applied to it also.

See also

References

  1. Debnath, Lokenath (2015). Integral transforms and their applications. CRC Press. ISBN 978-1-4822-2357-6. OCLC 919711727.

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