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Lake in Brevard County, Florida, United States
Sawgrass Lake
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Little Sawgrass Lake is close to the larger Sawgrass Lake, only 0.1 miles (0.16 km) away (28°04′30″N 80°46′41″W / 28.07500°N 80.77806°W / 28.07500; -80.77806.). The westernmost point is slightly west of the bigger lake. It also has a surface area under 1,000 acres (4 km), and is almost 2 miles (3.2 km) in diameter.